By the end of the lesson, you will be able to:
- Decide which of two triangles has the longer third side or larger included angle when two corresponding sides are equal, justifying with SAS-inequality reasoning in at least 4 comparison items with ≥ 85% accuracy.
- Use the triangle inequality to determine the possible range of a third side given two side lengths, and to test validity of three side lengths, in at least 6 tasks with complete inequality work shown.
- Solve real-world design-navigation problems that require comparing an included angle or an opposite side using SAS-inequality logic and triangle inequality, providing clear written justification in at least 3 word problems.
- Included angle - the angle formed by two given sides that share a common endpoint. Example: for sides and , the included angle is .
- SAS Inequality (hinge) - with two pairs of corresponding equal sides, the triangle with the larger included angle has the longer opposite third side, and conversely the triangle with the longer opposite third side has the larger included angle.
- Triangle inequality - in any triangle, the sum of the lengths of any two sides is greater than the length of the third side.
- Third-side range - all possible values for the unknown side that satisfy the triangle inequality.
- Converse comparison - if two sides are equal pairwise and the third side is longer in one triangle, then the included angle opposite it is larger in that triangle.
A) Identify an included angle - In triangle , for sides and , name the included angle.
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The included angle is formed at the shared endpoint , so it is .B) Quick triangle-validity test - Do lengths , , form a triangle? Use the three strict inequalities.
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is not strictly greater, so it fails. Not a triangle.C) Same two sides, different included angles - Two triangles have , . If and , which third side is longer: or ?
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Larger included angle gives longer opposite side. .D) Third-side range warm-up - If and , find the allowable range for .
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gives .1) Why today’s ideas matter
Imagine two folding frames made from the same pair of metal bars joined by a hinge. You open one a little wider than the other. Which frame has the longer base? You do not need a tape measure - just reasoning. Today, you will learn two powerful comparison tools that turn such questions into quick, logical decisions: a within-triangle rule that limits which lengths can form a triangle and tells you the full range of a missing side, and a between-triangles rule that compares opposite sides when two corresponding sides are fixed and the included angle changes, and conversely compares the included angles when the third sides change.
- Use the exterior-free inequality for within-triangle range decisions.
- Use side-angle hinge comparisons to rank opposite sides across two triangles with the same adjacent legs.
- Prove or explain with short, clear justifications.
2) Triangle inequality and third-side range
For side lengths , , within a single triangle:
This compresses to a third-side range:
Quick Demo A - Valid or not: Can segments , , form a triangle?
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Check ? It equals, not greater. Not a triangle.Quick Demo B - Third-side range: If , , then .
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Calculation: gives the open interval.Mini-summary: When two sides are fixed, the third side must fall strictly between their difference and their sum. Equality creates a straight, degenerate case.
3) SAS hinge: side vs included angle across two triangles
Statement: If triangles and satisfy , then . Conversely, if , then .
Guiding Check 1: With , and , compare and .
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Smaller included angle produces shorter opposite side. Therefore .Guiding Check 2: If the spans satisfy under the same leg pairs, what about the included angles?
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Equal opposite spans imply equal included angles: .Mini-summary: With two corresponding equal sides fixed, a more open hinge gives a longer opposite side, and a longer opposite side signals a more open hinge.
4) Blend the tools
Use triangle inequality to filter feasible third sides inside one triangle, then use the hinge comparison to rank designs across two triangles with the same legs.
Scenario Blend: Legs are m and . Range for base : . Compare two openings, vs : the larger angle yields the longer base.
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The candidate base m is invalid because it violates . With valid designs, gives the longer base.5) Real-world modeling
Construction - Two beams meet at a top joint; the base bay is opposite the joint. With the same beam lengths, opening the joint increases bay width.
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Making the included angle extremely small risks too small an opposite span and approaches a degenerate configuration.Navigation - With fixed legs km and , a larger turn yields a longer start-to-finish distance.
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If the straight distance falls short, increase the included angle to increase the opposite span.Sports - Two players keep fixed distances from a pivot. Opening the pivot angle widens the passing lane opposite the pivot.
Mini-summary: When two corresponding sides are fixed, opening the hinge lengthens the opposite side. The reverse is also true.
6) Common pitfalls
- Using a non-included angle in hinge reasoning.
- Allowing equality in triangle inequality. Equality collapses the triangle.
- Comparing triangles with different legs by angles alone.
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The angle must be the included angle between the two fixed sides because the opposite span is controlled by that angle. Non-included angles do not determine the span across those sides.7) References
- Big Ideas Math - Inequalities in one triangle; SAS hinge comparisons.
- CK-12 - Triangle inequality and third-side bounds.
- MathBitsNotebook - SAS inequality (hinge) demonstrations and practice.
- Open geometry notes - Comparison theorems within and between triangles.
Example 1 - SAS forward: compare third sides from included angles
Two triangles have equal corresponding legs , . Their included angles are and . Decide which opposite third side is longer.
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With the same two adjacent sides, the triangle with the larger included angle has the longer opposite third side. Since , we get .Example 2 - SAS converse: compare included angles from third sides
Two triangles have , . The measured third sides are and . Which included angle is larger?
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Longer opposite third side implies larger included angle when adjacent side pairs are equal. Thus .Example 3 - Triangle inequality: third-side range and candidates
A triangle has , . Find the allowable range for . Check and .
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Range . Both 13 and 12.9 lie in the open interval. Possible.Example 4 - Mixed design: filter by range, then compare by hinge
Legs m and . Give the base range and decide which opening, or , yields a longer base. Is feasible?
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Range . With the same legs, gives the longer base. A base of 0.6 m violates the lower bound, so not feasible.Example 5 - Edge case awareness
Can segments , , form a triangle? If not, describe the shape and how to fix it.
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gives a degenerate straight segment. Increase one of the shorter sides slightly or decrease the largest slightly to restore a strict inequality.- SAS forward - legs equal in pairs and , . Compare and .
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because the larger included angle faces the longer side. - SAS converse - legs equal in pairs and . Compare and .
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. - Third-side range - , . Find .
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. - Validity test - 6, 9, 14.
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Valid because . - Range then hinge - legs 1.4 m and 2.3 m. Range for base and which angle 42° or 88° gives longer base?
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Range . The 88° setting produces the longer base. - Achievability - legs 0.9 km and 1.7 km. Target straight distance 2.55 km?
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Range . 2.55 km is feasible by opening the angle sufficiently. - Rank bases by angle - 25°, 60°, 95°, 120°.
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Order: 25° < 60° < 95° < 120°. - Not enough information - only , and . Can we conclude ?
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No. Two corresponding side pairs must be equal to use the hinge comparison. - Integer values - sides 8 and 15. List integer third sides.
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All integers 8 through 22 inclusive satisfy . - Identify valid sets - (3,8,12), (5,9,13), (6.5,6.5,13.1).
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(3,8,12) not valid, (5,9,13) valid, (6.5,6.5,13.1) not valid.
- Legs equal in pairs. , . Compare and .
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. - Converse hinge. , with equal legs.
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. - Validity of 7, 9, 17.
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Not valid since - Range for with , .
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. - Order opposite sides by angle - 32°, 74°, 91°, 119°.
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32° < 74° < 91° < 119°. - Feasibility with legs 1.1 and 1.9 km for 3.2 km straight distance.
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Not achievable because . - How many integers for third side if sides are 9 and 14?
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17 values: 6 through 22 inclusive. - Can 4.2, 4.2, 8.4 form a triangle?
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No. Equality creates a degenerate segment. - Base X longer than base Y with equal legs. Which hinge is larger?
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Design X has the larger included angle. - Legs 2.0 m and 3.1 m. Range for base and which opening 38° or 82° is longer?
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Range . The 82° opening yields a longer base. - Choose all valid sets: (6,7,14), (5,9,15), (10,12,21).
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Only (10,12,21) is valid. - Complete the third inequality: .
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. - Why does equality fail in triangle inequality?
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Equality is collinear and encloses no area. It is not a triangle. - Parameter interval for if , .
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. - Why must the hinge angle be included?
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Because the opposite span is controlled by the angle between the fixed sides; non-included angles do not control that span.
Extension 1 - Threshold design
Equal legs 2.4 m each. Base must be at least 3.5 m. Is this possible, and should the included angle be small, moderate, or large?
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Range , so 3.5 m is possible. The included angle should be large to reach a larger opposite side.Extension 2 - Converse hinge from field measurement
Same legs; measured bases satisfy . What about the hinge angles?
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by the converse hinge comparison.Extension 3 - Max possible third side under a cap
With , , state the range for . If a cap is cm, does it cover all possible triangles?
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. A 20 cm cap excludes values in , so it does not cover all triangles.Extension 4 - Route planning
Legs 1.3 km and 2.6 km. Can you cross a 3.7 km river by adjusting only the turn?
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Range , so yes by opening the turn sufficiently.Extension 5 - Indirect reasoning in a spec
Client claims: same legs and equal hinge angles but different base lengths. Is this possible?
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No. With equal legs and equal included angles, opposite bases must match. The claim leads to contradiction.Write in your notebook. Choose one prompt.
Option A - 3-2-1
- 3 insights about how the included angle controls the opposite side when two adjacent sides are fixed.
- 2 decisions you can now make faster in real situations and why.
- 1 question you still have about using ranges or the hinge idea.
Option B - Checklist
- I can compute a valid third-side interval using the difference-and-sum form.
- I can determine which base is longer when two corresponding sides are equal in both designs.
- I can use a converse argument when angles are unknown but opposite sides are measured.
- I can reject edge cases that only meet equality in the triangle inequality.
Optional sketch - Draw two triangles with the same pair of adjacent sides. Label a smaller included angle in one and a larger included angle in the other. Note how the opposite third side compares.

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